Project Euler Problem 1: Multiples of 3 and 5¶
The source code for this problem can be found here.
Problem Statement¶
If we list all the natural numbers below \(10\) that are multiples of \(3\) or \(5\), we get \(3, 5, 6\) and \(9\). The sum of these multiples is \(23\).
Find the sum of all the multiples of \(3\) or \(5\) below \(1000\).
Solution Discussion¶
Nothing sophisticated here, explicitly perform the computation.
Solution Implementation¶
def solve():
""" Compute the answer to Project Euler's problem #1 """
num_range = range(1, 1000)
valid = lambda n: n % 3 == 0 or n % 5 == 0 # number must be a multiple of 3 OR 5
numbers = [i for i in num_range if valid(i)]
answer = sum(numbers)
return answer
expected_answer = 233168

solutions.problem1.
solve
()¶ Compute the answer to Project Euler’s problem #1